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  • IMAT 2013 Q56 Physics and Mathematics

  • Nicolas Sanchez

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    June 21, 2021 at 9:51 am
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    Which of the following is the equation of the circle with centre (­1.5, 0.5) and radius 3?

    A. 2x^2 – 6x + 2y^2 + 2y – 13 = 0

    B. 2x^2 + 6x + 2y^2 – 2y – 14 = 0

    C. 2x^2 – 6x + 2y^2 – 2y – 13 = 0

    D. 2x^2 + 6x + 2y^2 – 2y – 13 = 0

    E. 2x^2 + 6x + 2y^2 – 2y – 23 = 0

    answer original format:

  • MANISH MULCHANDANI

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    July 15, 2021 at 11:29 pm
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    Answer= D

    For this question, you should know the equation of circle.

    The equation of circle is-> (x-h)^2 + (y-k)^2=r^2

    where, (h,k)= centre of circle

    (r)= radius of circle

    Put the given values in above equation and you will get required one.

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