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  • BMAT 2003 Section 2 Q4

  • Ari Horesh

    June 21, 2021 at 4:13 pm
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    The diagram shows a uniform beam pivoted at its centre. The bar weighs 800N, and three
    other forces act on it as shown. Distance x can be varied.

    [picture attached]

    What value of distance x would cause the beam to be balanced?
    A 5 cm
    B 10 cm
    C 20 cm
    D 30 cm
    E 40 cm

  • EnterMedSchool Team

    June 24, 2021 at 7:14 am
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    Down Accepted answer

    if the pivot is located in the middle of a bar, we can ignore the bar weight itself. but if the pivot were not in the middle, we had to add its relative weight into the two sides of the equation. any way:

    500 x 0.2 = 0.4 x 200 200x

    solving this gives you 0.1m .

    – Ari

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