Find worked solutions for different exam papers, ask questions and connect with
medical aspirants and students from all over the world.

Home Forums BMAT Exam BMAT – Problem Solving and Discussion BMAT 2003 Section 2 Q4

  • BMAT 2003 Section 2 Q4

  • Ari Horesh

    Administrator
    June 21, 2021 at 4:13 pm
    934 Replies
    518176 XP
    Contributions: Team Manager
    Reputation: Level 9
    Up
    0
    Down

    The diagram shows a uniform beam pivoted at its centre. The bar weighs 800N, and three
    other forces act on it as shown. Distance x can be varied.

    [picture attached]

    What value of distance x would cause the beam to be balanced?
    A 5 cm
    B 10 cm
    C 20 cm
    D 30 cm
    E 40 cm

  • EnterMedSchool Team

    Member
    June 24, 2021 at 7:14 am
    131 Replies
    26550 XP
    Reputation: Level 5
    Up
    0
    Down Accepted answer

    if the pivot is located in the middle of a bar, we can ignore the bar weight itself. but if the pivot were not in the middle, we had to add its relative weight into the two sides of the equation. any way:

    500 x 0.2 = 0.4 x 200 200x

    solving this gives you 0.1m .

    – Ari

Sort by:
Viewing 1 - 2 of 2 replies

Log in to reply.

Original Post
0 of 0 posts June 2018
Now